求一个数的逆续输出
＃include<stdio.h>#define n 20main(){ int m,j,k,b[n]; j=0; printf("please input number:\n"); scanf("%d",&m); while(m!=0) { b[j]=m-(m/10)*10; m=m/10; j++; } for(k=0;k<j;k++) { printf("%d\n",b[k]); }}注：b[j]=m-(m/10)...